Keyword.merge
You're seeing just the function
merge, go back to Keyword module for more information.
Specs
Merges two keyword lists into one.
All keys, including duplicated keys, given in keywords2 will be added
to keywords1, overriding any existing one.
There are no guarantees about the order of keys in the returned keyword.
Examples
iex> Keyword.merge([a: 1, b: 2], [a: 3, d: 4])
[b: 2, a: 3, d: 4]
iex> Keyword.merge([a: 1, b: 2], [a: 3, d: 4, a: 5])
[b: 2, a: 3, d: 4, a: 5]
iex> Keyword.merge([a: 1], [2, 3])
** (ArgumentError) expected a keyword list as the second argument, got: [2, 3]
Specs
Merges two keyword lists into one.
All keys, including duplicated keys, given in keywords2 will be added
to keywords1. The given function will be invoked to solve conflicts.
If keywords2 has duplicate keys, the given function will be invoked
for each matching pair in keywords1.
There are no guarantees about the order of keys in the returned keyword.
Examples
iex> Keyword.merge([a: 1, b: 2], [a: 3, d: 4], fn _k, v1, v2 ->
...> v1 + v2
...> end)
[b: 2, a: 4, d: 4]
iex> Keyword.merge([a: 1, b: 2], [a: 3, d: 4, a: 5], fn :a, v1, v2 ->
...> v1 + v2
...> end)
[b: 2, a: 4, d: 4, a: 5]
iex> Keyword.merge([a: 1, b: 2, a: 3], [a: 3, d: 4, a: 5], fn :a, v1, v2 ->
...> v1 + v2
...> end)
[b: 2, a: 4, d: 4, a: 8]
iex> Keyword.merge([a: 1, b: 2], [:a, :b], fn :a, v1, v2 ->
...> v1 + v2
...> end)
** (ArgumentError) expected a keyword list as the second argument, got: [:a, :b]