LibreOffice 25.2 Help
Returns the number of date or time intervals between two given date values.
DateDiff (interval As String, date1 As Date, date2 As Date [, firstDayOfWeek As Integer [, firstWeekOfYear As Integer]]) As Double
A number.
interval - A string expression from the following table, specifying the date or time interval.
date1, date2 - The two date values to be compared.
firstdayofweek: An optional parameter that specifies the starting day of a week.
| firstdayofweek value | Explanation | 
|---|---|
| 0 | Use system default value | 
| 1 | Sunday (default) | 
| 2 | Monday | 
| 3 | Tuesday | 
| 4 | Wednesday | 
| 5 | Thursday | 
| 6 | Friday | 
| 7 | Saturday | 
firstweekofyear: An optional parameter that specifies the starting week of a year.
| firstweekofyear value | Explanation | 
|---|---|
| 0 | Use system default value | 
| 1 | Week 1 is the week that includes 1st January (default) | 
| 2 | Week 1 is the first week containing four or more days of that year | 
| 3 | Week 1 is the first week containing only days of the new year | 
Sub example_datediff
    MsgBox DateDiff("d", #1/1/2005#, #2005-12-31#)
End Sub